Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return false.
There may be duplicates in the original array.
Note: An array A rotated by x positions results in an array B of the same length such that B[i] == A[(i+x) % A.length] for every valid index i.
1 <= nums.length <= 1001 <= nums[i] <= 100nums = [3,4,5,1,2]truenums = [2,1,3,4]falsenums = [1,2,3]true